Tan4a-tan2a sec4a-sec2a
WebTan 4 A - Tan 2 A = 1 Formula used: Sec 2 A - Tan 2 A = 1 Calculation: Tan 4 A - Tan 2 A = 1 ⇒ Tan 4 A = 1 + Tan 2 A ⇒ Tan 4 A = Sec 2 A ⇒ Sec 2 A = Tan 4 A ---- (1) ⇒ SecA = Tan 2 A ----2) From (1) and (2) Sec 2 A - SecA = Tan 4 A - Tan 2 A ⇒ Sec 2 A - SecA = 1 ∴ The value of Sec2A - SecA is 1. Download Solution PDF Share on Whatsapp
Tan4a-tan2a sec4a-sec2a
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Web2sec 2A−sec 4A−2cosec 2A+cosec 4A=cot 4A−tan 4A. Medium Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions Prove the following statement. (sinA+cosA)(cotA+tanA)=secA+cosecA. Medium View solution > proove cotA+tanAcosecA =cosA Medium View solution > View more Click a picture with our app and get instant … Prove: sec^4A - sec^2A = tan^4A + tan^2A Question Prove: sec 4A−sec 2A=tan 4A+tan 2A Easy Solution Verified by Toppr sec 4A−sec 2A=sec 2A(sec 2A−1) =(1+tan 2A)(1+tan 2A−1) =tan 2A+tan 4A Was this answer helpful? 0 0 Similar questions Solve: (secA+cosA)(secA−cosA)=tan 2A+sin 2A Medium View solution >
WebQuestion: Sec2A+Tan2A= (1-Sin4A)Sec4A How to verify the identity by only changing the left side? This problem has been solved! You'll get a detailed solution from a subject … WebHow do I prove 1 + tan2A tanA = sec2A using the trigonometric addition or difference formulae? [math]1 + \tan 2A \tan A = [/math] [math]\displaystyle 1 + \frac {\sin 2A} {\cos 2A} \frac {\sin A} {\cos A} = [/math] (this uses the trig addition formulae: [math]\sin 2A = 2 \sin A \cos A [/math], and [math]\cos 2A = \cos^2 A - \sin^2 A [/math])
WebMay 21, 2024 · Abhishek K. May 21, 2024. LH S = tanA(1 + sec2A) = tanA(1 + 1 cos2A) = tanA( 1 + cos2A cos2A) = 1 cos2A[tanA ⋅ 2cos2A] = 1 cos2A[ sinA cosA ⋅ 2cos2A] = sin2A cos2A = RH S. Answer link. WebProve that:sec8A 1/ sec4A 1 = tan8A/tan2A. Byju's Answer Standard XII Mathematics Algebra of Derivatives Prove that:se... Question Prove that: ( s e c 8 A - 1) ( s e c 4 A - 1) = tan 8 A tan 2 A. Solution Given: we have ( s e c 8 A - 1) ( s e c 4 A - …
WebMay 25, 2024 · Explanation: tan3A− 1 tanA −1 = sec2A +tanA. = sec2A+ tanA, as desired!
WebMay 21, 2024 · = tan2A +sec2A = RH S Answer link Dean R. May 21, 2024 It seemed easier to start from the right; please see proof below. Explanation: We need the crudest cosine double angle formula: cos(2A) = cos(A + A) = cos2A− sin2A sin(2A) = sin(A +A) = 2sinAcosA tan2A +sec2A = sin2A cos2A + 1 cos2A = 1 + sin2A cos2A = 1 +2sinAcosA cos2A− sin2A public radio holiday specialsWebSec2A - Tan2A Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA) / (Cos 2 A - Sin 2 A) Make use of 1 = Cos 2 x + Sin 2 x and Difference of two squares = (Cos 2 A + Sin 2 A - 2SinACosA) / (CosA + SinA) (CosA - SinA) Factorise the numerator = (CosA - SinA) 2 / … public radio fort collins coloradoWebShow that Sec2A - Tan2A = (CosA-SinA)/ (CosA+SinA) Sec2A - Tan2A Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double … public radio music dayWebHow do I prove 1 + tan2A tanA = sec2A using the trigonometric addition or difference formulae? [math]1 + \tan 2A \tan A =[/math] [math]\displaystyle 1 + \frac{\sin 2A}{\cos … public radio podcast directoryWeb#mathprove that 1 + tan2A tanA = sec2Aclass 11th ,12th examination math questions and answer examples. public radio fresh air with terry grossWebExplanation: Use one of the Pythagorean identity namely, sec2A=1+tan2A sec4A−sec2A = (sec2A)2−sec2A = (1+tan2A)2− (1+tan2A) =1+2tan2A+tan4A−1−tan2A =tan4A+tan2A 2Thank You ANSWER Related Questions 5 chairs and 4 tables together cost ₹ 5600, while 4 chairs and 3 tables together cost ₹ 4340. Find the cost of a chairs and that of a table public radio for the front rangeWebClick here👆to get an answer to your question ️ Prove that: ( tan4A + tan2A ) ( 1 - tan^23A tan^2A ) = 2tan 3A sec^2A public radio nerd t shirt