WebIn circuit arrangement shown two cells supply a current I to a load resistarre R = 9 Ω. One cell has an emf E 1 = 9 V and internal resistance r 1 = 1 Ω and another cell has an emf E 2 = 6 V and internal resistance r 2 = 3 Ω. The current are as shown,then WebDec 10, 2024 · The electromotive force (EMF) is the maximum potential difference between two electrodes of a galvanic or voltaic cell. This quantity is related to the tendency for an element, a compound or an ion to acquire (i.e. gain) or release (lose) electrons. For example, the maximum potential between Zn and Cu of a well known cell.
In case the two cells are identical each of emf E=5v and internal ...
WebMay 8, 2024 · Two cells of emf E1 and E2 (E1 > E2) are connected as shown in figure. When a potentiometer is… Two identical parallel plate capacitors are connected in series and then joined in series with a… Two cells of emfs approximately 5V and 10V are to be accurately compared using a potentiometer of… Why is an ammeter connected in series ? WebTake these two resistors in parallel, and think about what the equivalent resistance would be. And we have seen that before. One over the equivalent resistance is going to be equal to one over 6.0 ohms plus one over 12.0 ohms. 1/6 is the same thing as two over 12. So 2/12 plus 1/12 is 3/12. And 3/12, you could view that as the same thing as one ... siem reap houses for rent
Describe how a potentiometer is used to compare the emfs of two cells …
WebTwo cells of emfs approximately 5V and 10V are to be accurately compared using a poteniometer ... used for comparing resistances and not voltages. WebAnswer (1 of 6): This circuit will create a short circuit between the cells. The difference in voltage will cause all the cells to equalise - if the voltage-charge was linear, then all cells would become 3v (but in reality it is more complex … WebTwo cells of emf’s approximately 5V and 10V are to be accurately compared using a potentiometer of length 400cm.a) The battery that runs the potentiometer sh... the pou3f2